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Heyte
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Posted - 2009.01.14 09:05:00 -
[1]
I'd just like to point out that there's no definitive terminology or formulae in the evelopedia on the different factors of combat. The only one I saw, in fact, was tracking speed, however the formula listed two variables that were undefined ('a' and 'h' in asinh?).
If anyone could link me to a definitive resource on combat formulas and each little nitty gritty factor in combat (including what each name does), it would be much appreciated.
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ry ry
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Posted - 2009.01.14 09:34:00 -
[2]
don't CCP keep some of eve's inner workings secret?
then again, there is some client source kicking around the internet. presumably not *all* calculations are made server-side, maybe you can find what you're looking for there?
CCP will ban you for touching the leaked source with a 10ft barge-pole though.
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Heyte
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Posted - 2009.01.14 10:46:00 -
[3]
Well, could someone at least tell me what each name does? :P
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Nick Seafort
Gallente Independent Contract Agency
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Posted - 2009.01.14 10:57:00 -
[4]
sinh is a hyperbolic trig function, often pronounced "sinch". The a infrotn of a trig function is one of the ways of stating it is an inverse trig function - asin, arcsin, or sin^-1
So, it's using the inverse sinh function. |
Heyte
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Posted - 2009.01.15 05:31:00 -
[5]
Much appreciated.
Any more help on names?
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Heyte
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Posted - 2009.01.15 07:03:00 -
[6]
Edited by: Heyte on 15/01/2009 07:03:58 Alright, well according to wiki sinh^-1 is x = In(x+(root)x^2+1(/root)) where In = Integral
How exactly do you apply In as a coefficient to the formula? Also, there's suddenly a whole new list of variables that are undefined from getting this formula.
Math people wanna help me out?
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Aisley Tyrion
DAB G00DFELLAS
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Posted - 2009.01.15 07:25:00 -
[7]
Edited by: Aisley Tyrion on 15/01/2009 07:35:29
Originally by: Heyte Edited by: Heyte on 15/01/2009 07:03:58 Alright, well according to wiki sinh^-1 is x = In(x+(root)x^2+1(/root)) where In = Integral
How exactly do you apply In as a coefficient to the formula? Also, there's suddenly a whole new list of variables that are undefined from getting this formula.
Math people wanna help me out?
The integral is not a coefficient, it's an operator. It is analogous a continuous sum across given range of the variable. However, there is probably a much easier way to solve the equation you're looking at than integrating. Perhaps you could link the page where you found the tracking formula since I'm unable to locate the page.
Edit: Come to think of it, you most likely don't even want solve the equation since it probably is in a form that gives the hit change as default (I'm assuming that is what you want to find out). If so you just enter the values for all the variables and use a calculator to evaluate the answer.
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Culmen
Caldari Blood Phage Syndicate R.E.P.O.
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Posted - 2009.01.15 07:35:00 -
[8]
Edited by: Culmen on 15/01/2009 07:42:23
Originally by: Aisley Tyrion
Originally by: Heyte Edited by: Heyte on 15/01/2009 07:03:58 Alright, well according to wiki sinh^-1 is x = In(x+(root)x^2+1(/root)) where In = Integral
How exactly do you apply In as a coefficient to the formula? Also, there's suddenly a whole new list of variables that are undefined from getting this formula.
Math people wanna help me out?
The integral is not a coefficient, it's an operator. It is analogous a continuous sum across given range of the variable. However, there is probably a much easier way to solve the equation you're looking at than integrating. Perhaps you could link the page where you found the tracking formula since I'm unable to locate the page.
Also are you sure it is 'I'n not 'L'n, the two might look similar if written as "ln"
but still it is an operator, with Ln being the Natural Logarithm
I find it far more likely for it to be the natural log, since preforming an intergration would result in another function and not an output
EDIT: just checked the wiki and I can confirm you are looking for the Natural Logarithm, 'L'n fortunately most scientific calculators, including the one on windows, have the Ln function. and further more why do i even need a sig? |
Aisley Tyrion
DAB G00DFELLAS
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Posted - 2009.01.15 07:38:00 -
[9]
Edited by: Aisley Tyrion on 15/01/2009 07:40:11
Originally by: Culmen I find it far more likely for it to be the natural log, since preforming an intergration would result in another function and not an output
It would result in a definite value if it's a definite integral.
And yes in fact the "ln" is a natural logarithm as per definition of arcsinh. I thought the OP had thought that through and just went along, silly me.
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Culmen
Caldari Blood Phage Syndicate R.E.P.O.
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Posted - 2009.01.15 07:48:00 -
[10]
Edited by: Culmen on 15/01/2009 07:53:14 Edited by: Culmen on 15/01/2009 07:48:54
Originally by: Aisley Tyrion
Originally by: Culmen I find it far more likely for it to be the natural log, since preforming an intergration would result in another function and not an output
It would result in a definite value if it's a definite integral.
And yes in fact the "ln" is a natural logarithm as per definition of arcsinh. I thought the OP had thought that through and just went along, silly me.
upon further examination, looks like the OP is closer then I thought for the derivative of sinh^-1 is actually (1+x^2)^-.5 basically what the OP said but to the OP ln is alot easier to calculate
PS Aisley, I concede the point about definite values, but you get what I'm going for |
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Heyte
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Posted - 2009.01.15 07:52:00 -
[11]
Linkage
Sorry, it's referred to as targeting speed, actually. |
Culmen
Caldari Blood Phage Syndicate R.E.P.O.
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Posted - 2009.01.15 08:01:00 -
[12]
Edited by: Culmen on 15/01/2009 08:01:39
Originally by: Heyte Linkage
Sorry, it's referred to as targeting speed, actually.
that better asinh = Area Hyperbolic Sine aka Inverse Hyperbolic Sine more commonly put as Arsinh or sinh^-1 so you got the right forumla, you just need to take the natural log of ((sig radius) + (sig radius^2 + 1)^.5 and further more why do i even need a sig? |
Heyte
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Posted - 2009.01.16 01:56:00 -
[13]
Just curious: how'd you get to that formula, Culmen? |
Fyrewyre
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Posted - 2009.01.16 02:15:00 -
[14]
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Fyrewyre
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Posted - 2009.01.16 02:16:00 -
[15]
Please visit your user settings to re-enable images. |
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